Time, Speed & Distance
JKSSB Assistant Training Officer (Handicrafts & Handlooms) · Numerical Ability · 10 practice questions with answers and explanations: 0 Easy, 10 Medium, 0 Hard.
Sample questions
Sample Medium question 1
Arjun, while going to college, walks at 9/10 of his usual speed and reaches 10 minutes late. Find his usual time to reach college.
- 10 minutes
- 85 minutes
- 100 minutes
- 90 minutes
Show answer
Answer: D. Speed ratio = 10 : 9 (usual : reduced), so time ratio = 9 : 10. The 1 part of the time difference equals 10 min, so usual time (9 parts) = 90 minutes.
Sample Medium question 2
Meera, while going to school, walks at 9/10 of his usual speed and reaches 6 minutes late. Find his usual time to reach school.
- 51 minutes
- 54 minutes
- 6 minutes
- 60 minutes
Show answer
Answer: B. Speed ratio = 10 : 9 (usual : reduced), so time ratio = 9 : 10. The 1 part of the time difference equals 6 min, so usual time (9 parts) = 54 minutes.
Sample Medium question 3
Imran, while going to office, walks at 2/3 of his usual speed and reaches 20 minutes late. Find his usual time to reach office.
- 60 minutes
- 40 minutes
- 20 minutes
- 30 minutes
Show answer
Answer: B. Speed ratio = 3 : 2 (usual : reduced), so time ratio = 2 : 3. The 1 part of the time difference equals 20 min, so usual time (2 parts) = 40 minutes.
More Numerical Ability topics for JKSSB Assistant Training Officer (Handicrafts & Handlooms)
- Average
- Boats & Streams
- HCF & LCM
- Mixture & Alligation
- Number System
- Partnership
- Percentage
- Problems on Ages
- Problems on Trains
- Profit/Loss & Discount
- Ratio & Proportion
- Simple & Compound Interest
- Time & Work / Pipes & Cisterns