Columns, Bond and Shear

JKSSB Junior Engineer (Civil) · RCC Structures · 17 practice questions with answers and explanations: 10 Easy, 2 Medium, 5 Hard.

Sample questions

Sample Easy question 1

A column is classed as short when the ratio of its effective length to its lateral dimension is less than:

  1. 20
  2. 40
  3. 12
  4. 6
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Answer: C. A column with a ratio above 12 is a long column and needs a slenderness check.

Sample Easy question 2

The minimum lap length for bars in tension is the development length or:

  1. 30 φ, whichever is greater
  2. 10 φ
  3. 5 φ
  4. 100 φ
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Answer: A. Splices should be staggered and kept away from regions of high stress.

Sample Easy question 3

The minimum percentage of longitudinal steel in a reinforced concrete column is:

  1. 0.12%
  2. 4%
  3. 0.8% of the gross area
  4. 2%
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Answer: C. The maximum is 6% of the gross area, and in practice 4% is used to avoid congestion.

Sample Medium question 4

The anchorage value of a standard 180° hook (U-type) in a bar of diameter φ is:

  1. 30 φ
  2. 16 φ
  3. 4 φ
  4. 8 φ
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Answer: B. A standard 90° bend gives 8 φ.

Sample Medium question 5

A beam of 230 mm width and 450 mm effective depth carries a design shear force of 150 kN. The nominal shear stress is about:

  1. 1.45 N/mm²
  2. 0.145 N/mm²
  3. 2.9 N/mm²
  4. 0.65 N/mm²
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Answer: A. τv = Vu ÷ (b d) = 150,000 ÷ (230 × 450) = 1.45 N/mm².

Sample Hard question 6

A short column of 400 mm × 400 mm in M25 concrete has eight 16 mm bars of Fe 415 steel (1,608 mm²). Its axial capacity Pu = 0.4 fck Ac + 0.67 fy Asc is about:

  1. 1,600 kN
  2. 2,031 kN
  3. 1,016 kN
  4. 4,062 kN
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Answer: B. 0.4 × 25 × 158,392 + 0.67 × 415 × 1,608 = 2,031 kN.

Sample Hard question 7

For a 20 mm deformed Fe 500 bar in M25 concrete (design bond stress 2.24 N/mm²), the development length is about:

  1. 400 mm
  2. 971 mm
  3. 1,940 mm
  4. 485 mm
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Answer: B. Ld = φ × 0.87 fy ÷ (4 τbd) = 20 × 435 ÷ (4 × 2.24) = 971 mm.

Sample Hard question 8

The minimum eccentricity of a column of unsupported length 3,000 mm and lateral dimension 300 mm is the larger of l ÷ 500 + D ÷ 30 and 20 mm, which is:

  1. 20 mm
  2. 6 mm
  3. 10 mm
  4. 16 mm
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Answer: A. l ÷ 500 + D ÷ 30 = 6 + 10 = 16 mm, which is less than 20 mm.

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