Problems on Ages

JKSSB Junior Assistant · Numerical Ability · 12 practice questions with answers and explanations: 2 Easy, 6 Medium, 4 Hard.

Sample questions

Sample Easy question 1

A father is four times as old as his son. If the sum of their ages is 50 years, how old is the son?

  1. 12
  2. 8
  3. 40
  4. 10
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Answer: D. Son = x, father = 4x. 5x = 50, so x = 10.

Sample Medium question 2

The sum of the present ages of X and Y is 50 years. Five years ago, X was three times as old as Y. Find X's present age.

  1. 30
  2. 15
  3. 40
  4. 35
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Answer: D. x − 5 = 3(y − 5) and x + y = 50. Substituting x = 50 − y: 45 − y = 3y − 15, so y = 15 and x = 35.

Sample Hard question 3

Ten years ago a father was 12 times as old as his son; ten years from now he will be twice as old as his son. Find the son's present age.

  1. 14
  2. 15
  3. 10
  4. 12
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Answer: D. f − 10 = 12(s − 10) and f + 10 = 2(s + 10). Eliminating f: 12s − 110 = 2s + 10, so s = 12 (and f = 34).

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