Shear Force and Bending Moment
JKSSB Junior Engineer (Civil) · Mechanics and Structural Analysis · 17 practice questions with answers and explanations: 10 Easy, 7 Medium, 0 Hard.
Sample questions
Sample Easy question 1
At the point of contraflexure of a beam:
- The bending moment changes sign
- The deflection is maximum
- The slope is zero
- The shear force is zero
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Answer: A. The bending moment passes through zero and the curvature reverses.
Sample Easy question 2
The shear force at a section is the:
- Rate of change of bending moment
- Square of the moment
- Rate of change of load
- Integral of the deflection
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Answer: A. V = dM ÷ dx.
Sample Easy question 3
The fixed-end moment for a fixed beam of span L carrying a uniformly distributed load w is:
- wL² ÷ 12
- wL² ÷ 2
- wL² ÷ 8
- wL² ÷ 24
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Answer: A. For L = 6 m and w = 12 kN/m the fixed-end moment is 36 kN·m.
Sample Medium question 4
A beam overhangs its support by 2 m and carries a UDL of 10 kN/m on the overhang. The bending moment at the support is:
- 20 kN·m
- 40 kN·m
- 5 kN·m
- 10 kN·m
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Answer: A. M = wL² ÷ 2 = 10 × 4 ÷ 2 = 20 kN·m (hogging).
Sample Medium question 5
A simply supported beam of 4 m span carries a central point load of 40 kN. The maximum bending moment is:
- 80 kN·m
- 20 kN·m
- 160 kN·m
- 40 kN·m
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Answer: D. M = WL ÷ 4 = 40 × 4 ÷ 4 = 40 kN·m.
Sample Medium question 6
A simply supported beam of 5 m span carries a uniformly distributed load of 12 kN/m. The maximum bending moment is:
- 150 kN·m
- 18.75 kN·m
- 75 kN·m
- 37.5 kN·m
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Answer: D. M = wL² ÷ 8 = 12 × 25 ÷ 8 = 37.5 kN·m.