Shear Strength and Earth Pressure
JKSSB Junior Engineer (Civil) · Soil Mechanics · 9 practice questions with answers and explanations: 4 Easy, 5 Medium, 0 Hard.
Sample questions
Sample Easy question 1
A clean dry sand has a cohesion of:
- Equal to the friction angle
- Equal to its unit weight
- High
- Zero
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Answer: D. Sands are cohesionless, and their strength comes from friction alone.
Sample Easy question 2
For a square footing, Terzaghi's cohesion term in the bearing capacity equation uses a shape factor of:
- 1.3
- 1.0
- 2.0
- 0.5
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Answer: A. qu = 1.3 c Nc + γ D Nq + 0.4 γ B Nγ.
Sample Easy question 3
A drained test on a sand in a direct shear box measures the angle of internal friction φ as the:
- Angle whose tangent is the ratio of shear strength to normal stress
- Angle of repose of the slope
- Angle of the shear box
- Angle of the failure plane to the vertical
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Answer: A. For dry sand, tan φ = τ ÷ σ.
Sample Medium question 4
The Rankine active earth pressure coefficient for φ = 30° is:
- 2/3
- 1/2
- 1/3
- 3
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Answer: C. Ka = (1 − sin 30°) ÷ (1 + sin 30°) = 0.5 ÷ 1.5 = 1/3.
Sample Medium question 5
The active thrust on a 4 m high smooth wall retaining dry cohesionless soil of unit weight 18 kN/m³ and φ = 30° is:
- 96 kN per metre
- 144 kN per metre
- 48 kN per metre
- 24 kN per metre
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Answer: C. Pa = ½ Ka γ H² = ½ × (1/3) × 18 × 16 = 48 kN/m.
Sample Medium question 6
A soil has c = 20 kPa and φ = 30°. Under an effective normal stress of 100 kPa, the shear strength is about:
- 50 kPa
- 120 kPa
- 57.7 kPa
- 77.7 kPa
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Answer: D. τ = c + σ' tan φ = 20 + 100 × 0.577 = 77.7 kPa.