Mixture & Alligation
JKSSB Junior Engineer (Mechanical) · Mathematics · 47 practice questions with answers and explanations: 8 Easy, 33 Medium, 6 Hard.
Sample questions
Sample Easy question 1
A 50-litre mixture contains milk and water in the ratio 4:1. Find the quantity of water.
- 12
- 9
- 10
- 8
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Answer: C. Water = (1/5) × 50 = 10 litres.
Sample Easy question 2
A mixture of milk and water is in the ratio 5:2. If the total is 35 litres, find the quantity of water.
- 8 litres
- 12 litres
- 10 litres
- 9 litres
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Answer: C. Water = (2/7) × 35 = 10 litres.
Sample Easy question 3
A mixture of sugar solution has sugar and water in the ratio 3:7. If the total is 50 litres, find the quantity of sugar.
- 20 litres
- 18 litres
- 15 litres
- 12 litres
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Answer: C. Sugar = (3/10) × 50 = 15 litres.
Sample Medium question 4
Rice costing Rs. 45 per kg is mixed with rice costing Rs. 55 per kg in the ratio 3 : 1 by weight. What is the cost price of the mixture per kg?
- Rs. 47 1/2
- Rs. 44 1/2
- Rs. 49 1/2
- Rs. 50
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Answer: A. Mean price = (45 × 3 + 55 × 1) ÷ (3 + 1) = 47 1/2.
Sample Medium question 5
Rice costing Rs. 40 per kg is mixed with rice costing Rs. 60 per kg in the ratio 1 : 3 by weight. What is the cost price of the mixture per kg?
- Rs. 50
- Rs. 57
- Rs. 52
- Rs. 55
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Answer: D. Mean price = (40 × 1 + 60 × 3) ÷ (1 + 3) = 55.
Sample Medium question 6
Rice costing Rs. 50 per kg is mixed with rice costing Rs. 60 per kg in the ratio 4 : 1 by weight. What is the cost price of the mixture per kg?
- Rs. 49
- Rs. 55
- Rs. 52
- Rs. 54
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Answer: C. Mean price = (50 × 4 + 60 × 1) ÷ (4 + 1) = 52.
Sample Hard question 7
Two vessels contain milk and water in the ratios 2:3 and 5:3 respectively. In what ratio should quantities from the two vessels be mixed to get an equal (1:1) ratio of milk to water?
- 4:5
- 3:5
- 5:3
- 5:4
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Answer: D. Milk fractions are 0.4 and 0.625; by alligation for a target of 0.5, the ratio is (0.625-0.5):(0.5-0.4) = 5:4.
Sample Hard question 8
A container has a mixture of two liquids A and B in the ratio 7:5. When 9 litres of the mixture is drawn off and replaced with liquid B, the ratio becomes 7:9. Find the initial quantity of liquid A.
- 19.25 litres
- 20 litres
- 22.75 litres
- 21 litres
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Answer: D. Let total = 12x (A=7x, B=5x). Removing 9L keeps the 7:5 ratio in the remainder: A left = 7x − 5.25, B left = 5x − 3.75, and after adding back 9L of B: (7x−5.25)/(5x+5.25) = 7/9. Solving gives x = 3, so A = 7×3 = 21 litres.
Sample Hard question 9
In what proportion must water be mixed with milk costing Rs. 40/litre so that after selling the mixture at the cost price, there is a profit of 25%?
- 1:5
- 1:4
- 1:6
- 1:8
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Answer: B. For a 25% profit by dilution, the cost price of the mixture should be 40/1.25 = 32 per litre. By alligation with water at Rs. 0: ratio of water:milk = (40-32):(32-0) = 8:32 = 1:4.
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