Simple & Compound Interest
JKSSB Junior Engineer (Mechanical) · Mathematics · 49 practice questions with answers and explanations: 21 Easy, 27 Medium, 1 Hard.
Sample questions
Sample Easy question 1
At what rate of simple interest per annum will Rs. 12000 amount to Rs. 14400 in 4 years?
- 4%
- 5%
- 7%
- 6%
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Answer: B. Simple interest = 14400 − 12000 = Rs. 2400. Rate = (2400 × 100) ÷ (12000 × 4) = 5%.
Sample Easy question 2
At what rate of simple interest per annum will Rs. 8000 amount to Rs. 8960 in 2 years?
- 6%
- 8%
- 7%
- 5%
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Answer: A. Simple interest = 8960 − 8000 = Rs. 960. Rate = (960 × 100) ÷ (8000 × 2) = 6%.
Sample Easy question 3
At what rate of simple interest per annum will Rs. 12000 amount to Rs. 15000 in 5 years?
- 5%
- 4%
- 6%
- 7%
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Answer: A. Simple interest = 15000 − 12000 = Rs. 3000. Rate = (3000 × 100) ÷ (12000 × 5) = 5%.
Sample Medium question 4
A sum of Rs. 8000 becomes Rs. 9261 in 3 years at compound interest, compounded annually. Find the rate of interest.
- 7%
- 4%
- 5%
- 6%
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Answer: C. 9261/8000 = (1+r/100)³. Taking the cube root: 1+r/100 = 1.05, so r = 5%.
Sample Medium question 5
The compound interest on a sum for 2 years is Rs. 832, and the simple interest for the same period at the same rate is Rs. 800. Find the rate of interest.
- 7%
- 6%
- 8%
- 9%
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Answer: C. The difference (832-800=32) equals SI×(R/200) for 2 years, since CI-SI = SI×R/200 when SI is for the same period: 32 = 800×R/200, giving R = 8%.
Sample Medium question 6
A sum of money invested at compound interest amounts to Rs. 4840 in 2 years and Rs. 5324 in 3 years. Find the rate of interest.
- 10%
- 12%
- 9%
- 8%
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Answer: A. The interest earned in the 3rd year = 5324-4840 = 484, which is the interest on Rs. 4840 for 1 year. Rate = (484×100)/4840 = 10%.
Sample Hard question 7
Find the compound interest on Rs. 10,000 for 1.5 years at 10% per annum, compounded half-yearly.
- 1600
- 1576.25
- 1500
- 1550
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Answer: B. With 5% per half-year over 3 periods, amount = 10000 × 1.05³ ≈ 11576.25, so CI ≈ 1576.25.
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