Height & Distance

JKSSB Sub-Inspector (Telecommunication) · Basic Numeracy · 32 practice questions with answers and explanations: 10 Easy, 10 Medium, 12 Hard.

Sample questions

Sample Easy question 1

The angle of elevation of the top of a tower from a point 20 m away is 45°. Find the height of the tower.

  1. 15 m
  2. 18 m
  3. 20 m
  4. 25 m
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Answer: C. Height = distance × tan(45°) = 20 × 1 = 20 m.

Sample Medium question 2

From a point 30 m from a tower's base, the angle of elevation of its top is 60°. Find the tower's height (take √3 = 1.73).

  1. 48.9 m
  2. 50.1 m
  3. 51.9 m
  4. 53.2 m
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Answer: C. Height = distance × tan(60°) = 30 × 1.73 = 51.9 m.

Sample Hard question 3

A man standing on top of a 40 m tall building observes the angle of depression of a car to be 30°. After the car moves closer and the angle of depression becomes 60°, find the distance the car traveled (take √3 = 1.73).

  1. 42.1 m
  2. 46.2 m
  3. 48.5 m
  4. 50 m
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Answer: B. Initial distance = 40/tan(30°) = 40√3 = 69.2 m. Final distance = 40/tan(60°) = 40/√3 = 23.1 m. Distance traveled = 69.2 - 23.1 = 46.2 m (approx, using √3=1.73).

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