Problems on Ages
JKSSB Sub-Inspector (Telecommunication) · Basic Numeracy · 12 practice questions with answers and explanations: 2 Easy, 6 Medium, 4 Hard.
Sample questions
Sample Easy question 1
A father is four times as old as his son. If the sum of their ages is 50 years, how old is the son?
- 12
- 8
- 40
- 10
Show answer
Answer: D. Son = x, father = 4x. 5x = 50, so x = 10.
Sample Medium question 2
The average age of three persons is 24 years. If two of them are 20 and 26 years old, find the age of the third.
- 28
- 22
- 26
- 30
Show answer
Answer: C. Total = 3 × 24 = 72. Third = 72 − (20 + 26) = 26.
Sample Hard question 3
The present ages of A and B are in the ratio 4 : 5. Six years later the ratio will be 5 : 6. Find A's present age.
- 20
- 32
- 24
- 30
Show answer
Answer: C. (4k + 6)/(5k + 6) = 5/6 → 24k + 36 = 25k + 30 → k = 6. A = 4k = 24.
More Basic Numeracy topics for JKSSB Sub-Inspector (Telecommunication)
- Algebra
- Average
- Boats & Streams
- Data Interpretation
- Geometry
- HCF & LCM
- Height & Distance
- Mensuration
- Mixture & Alligation
- Number System
- Partnership
- Percentage
- Problems on Trains
- Profit/Loss & Discount
- Ratio & Proportion
- Simple & Compound Interest
- Simplification & Approximation
- Surds & Indices
- Time & Work / Pipes & Cisterns
- Time, Speed & Distance
- Trigonometry