Height & Distance
LSSSSB Non-Technical · Mathematics · 32 practice questions with answers and explanations: 13 Easy, 15 Medium, 4 Hard.
Sample questions
Sample Easy question 1
The angle of elevation of the top of a tower from a point 20 m away is 45°. Find the height of the tower.
- 20 m
- 18 m
- 15 m
- 25 m
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Answer: A. Height = distance × tan(45°) = 20 × 1 = 20 m.
Sample Easy question 2
A pole casts a shadow equal in length to its own height. Find the angle of elevation of the sun.
- 60°
- 30°
- 45°
- 90°
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Answer: C. When shadow length equals height, tan(angle) = height/shadow = 1, so the angle is 45°.
Sample Easy question 3
A ladder 10 m long rests against a wall, making a 30° angle with the ground. Find the height it reaches on the wall.
- 6 m
- 4 m
- 7 m
- 5 m
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Answer: D. Height = ladder length × sin(30°) = 10 × 0.5 = 5 m.
Sample Medium question 4
From a point on the ground, the angle of elevation of a 20 m tower's top is 30°. Find the distance of the point from the base.
- 40 m
- 34.6 m
- 28.5 m
- 30 m
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Answer: B. Distance = height/tan 30° = 20 × √3 ≈ 34.6 m.
Sample Medium question 5
From the top of a 60 m tower, the angle of depression to a car is 30°. Find the distance of the car from the base of the tower.
- 96 m
- 103.9 m
- 110 m
- 90 m
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Answer: B. Distance = 60/tan 30° = 60√3 ≈ 103.9 m.
Sample Medium question 6
A tower's shadow is 30 m long when the angle of elevation of the sun is 30°. Find the height of the tower.
- 15 m
- 20 m
- 17.3 m
- 25 m
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Answer: C. Height = 30 × tan 30° = 30/√3 ≈ 17.3 m.
Sample Hard question 7
A vertical pole and a tower stand on the same level ground. The angle of elevation of the top of the tower from the foot of the pole is 60°, and the angle of elevation of the top of the pole from the foot of the tower is 30°. If the pole is 15 m tall, find the height of the tower.
- 50 m
- 45 m
- 40 m
- 48 m
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Answer: B. Let the distance between them be d. Pole: 15 = d×tan(30°), so d = 15√3. Tower: height = d×tan(60°) = 15√3 × √3 = 45 m.
Sample Hard question 8
The angle of elevation of a tower's top changes from 30° to 60° as an observer moves 40 m closer. Find the height of the tower.
- 28.3 m
- 34.6 m
- 40 m
- 20 m
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Answer: B. Using h = d/(cot30° - cot60°) = 40/(√3 - 1/√3) = 20√3 ≈ 34.6 m.
Sample Hard question 9
From a point 60 m above a lake, the angle of elevation of a cloud is 30° and the angle of depression of its reflection is 60°. Find the height of the cloud above the lake.
- 150 m
- 195 m
- 165 m
- 180 m
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Answer: D. Solving the standard cloud-reflection formula gives a height of 120 m above the observer, i.e. 60+120 = 180 m above the lake.
More Mathematics topics for LSSSSB Non-Technical
- Algebra
- Average
- Boats & Streams
- Data Interpretation
- Geometry
- HCF & LCM
- Mensuration
- Mixture & Alligation
- Number System
- Partnership
- Percentage
- Problems on Ages
- Problems on Trains
- Profit/Loss & Discount
- Ratio & Proportion
- Simple & Compound Interest
- Simplification & Approximation
- Surds & Indices
- Time & Work / Pipes & Cisterns
- Time, Speed & Distance
- Trigonometry