Problems on Ages

Ladakh Police Sub-Inspector · Mathematics · 81 practice questions with answers and explanations: 43 Easy, 37 Medium, 1 Hard.

Sample questions

Sample Easy question 1

Farah is 45 years old now. How old was this person 11 years ago?

  1. 55
  2. 56
  3. 35
  4. 34
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Answer: D. 45 − 11 = 34 years.

Sample Easy question 2

The ages of Neha and Farah are in the ratio 1 : 3, and the sum of their ages is 12 years. What is the age of Farah (in years)?

  1. 3
  2. 4
  3. 12
  4. 9
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Answer: D. One part = 12/4 = 3; Farah's age = 3 × 3 = 9 years.

Sample Easy question 3

A mother is 5 times as old as the son. Their present ages add up to 120 years. What is the son's present age (in years)?

  1. 100
  2. 24
  3. 20
  4. 25
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Answer: C. Let son = x; 5x + x = 120, so x = 20.

Sample Medium question 4

The present ages of two brothers are in the ratio 5 : 3. After 4 years, the sum of their ages will be 48. Find the present age of the elder brother.

  1. 15 years
  2. 29 years
  3. 21 years
  4. 25 years
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Answer: D. Let the present ages be 5k and 3k. After 4 years: 5k + 3k + 8 = 48, so k = 5. The elder brother is 5 × 5 = 25 years old.

Sample Medium question 5

The present ages of two brothers are in the ratio 5 : 3. After 6 years, the sum of their ages will be 68. Find the present age of the elder brother.

  1. 35 years
  2. 29 years
  3. 41 years
  4. 21 years
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Answer: A. Let the present ages be 5k and 3k. After 6 years: 5k + 3k + 12 = 68, so k = 7. The elder brother is 5 × 7 = 35 years old.

Sample Medium question 6

The present ages of two brothers are in the ratio 4 : 2. After 6 years, the sum of their ages will be 54. Find the present age of the elder brother.

  1. 34 years
  2. 14 years
  3. 22 years
  4. 28 years
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Answer: D. Let the present ages be 4k and 2k. After 6 years: 4k + 2k + 12 = 54, so k = 7. The elder brother is 4 × 7 = 28 years old.

Sample Hard question 7

Ten years ago a father was 12 times as old as his son; ten years from now he will be twice as old as his son. Find the son's present age.

  1. 14
  2. 15
  3. 10
  4. 12
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Answer: D. f − 10 = 12(s − 10) and f + 10 = 2(s + 10). Eliminating f: 12s − 110 = 2s + 10, so s = 12 (and f = 34).

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