Time, Speed & Distance
Ladakh Police Sub-Inspector · Mathematics · 44 practice questions with answers and explanations: 15 Easy, 26 Medium, 3 Hard.
Sample questions
Sample Easy question 1
A cyclist travels at 15 km/h for 3 hours. Find the distance covered.
- 45 km
- 40 km
- 48 km
- 42 km
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Answer: A. Distance = speed × time = 15 × 3 = 45 km.
Sample Easy question 2
A car needs to cover 180 km at a speed of 45 km/h. Find the time taken.
- 4.5 hours
- 3.5 hours
- 3 hours
- 4 hours
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Answer: D. Time = distance/speed = 180/45 = 4 hours.
Sample Easy question 3
Convert a speed of 54 km/h into metres per second.
- 12 m/s
- 15 m/s
- 20 m/s
- 18 m/s
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Answer: B. Speed in m/s = km/h × 5/18 = 54 × 5/18 = 15 m/s.
Sample Medium question 4
Sandeep, while going to school, walks at 9/10 of his usual speed and reaches 6 minutes late. Find his usual time to reach school.
- 60 minutes
- 6 minutes
- 51 minutes
- 54 minutes
Show answer
Answer: D. Speed ratio = 10 : 9 (usual : reduced), so time ratio = 9 : 10. The 1 part of the time difference equals 6 min, so usual time (9 parts) = 54 minutes.
Sample Medium question 5
Arjun, while going to college, walks at 9/10 of his usual speed and reaches 10 minutes late. Find his usual time to reach college.
- 10 minutes
- 85 minutes
- 100 minutes
- 90 minutes
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Answer: D. Speed ratio = 10 : 9 (usual : reduced), so time ratio = 9 : 10. The 1 part of the time difference equals 10 min, so usual time (9 parts) = 90 minutes.
Sample Medium question 6
Meera, while going to school, walks at 9/10 of his usual speed and reaches 6 minutes late. Find his usual time to reach school.
- 51 minutes
- 54 minutes
- 6 minutes
- 60 minutes
Show answer
Answer: B. Speed ratio = 10 : 9 (usual : reduced), so time ratio = 9 : 10. The 1 part of the time difference equals 6 min, so usual time (9 parts) = 54 minutes.
Sample Hard question 7
A train overtakes two persons walking in the same direction at 3 km/h and 5 km/h respectively, and passes them in 10 and 11 seconds respectively. Find the speed of the train (in km/h).
- 27 km/h
- 23 km/h
- 25 km/h
- 29 km/h
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Answer: C. Since the train's length L is the same in both cases: (V-3)×10 = (V-5)×11 (using relative speed × time). This gives 10V-30 = 11V-55, so V = 25 km/h.
Sample Hard question 8
A thief is spotted by a policeman 200 m away. When the policeman starts chasing, the thief also starts running. If the thief's speed is 8 km/h and the policeman's speed is 10 km/h, find the distance the thief runs before being caught.
- 900 m
- 800 m
- 850 m
- 750 m
Show answer
Answer: B. Relative speed = 10-8 = 2 km/h. Time to close 200 m (0.2 km) gap = 0.2/2 = 0.1 hours. Distance thief runs = 8 × 0.1 = 0.8 km = 800 m.
Sample Hard question 9
Walking at 5 km/h, a man is 6 minutes late; walking at 6 km/h, he is 2 minutes early. Find the distance to his destination.
- 4 km
- 4.5 km
- 3 km
- 3.5 km
Show answer
Answer: A. The time difference is 8 minutes = 8/60 hr; solving d/5 - d/6 = 8/60 gives d = 4 km.
More Mathematics topics for Ladakh Police Sub-Inspector
- Algebra
- Average
- Boats & Streams
- Data Interpretation
- Geometry
- HCF & LCM
- Height & Distance
- Mensuration
- Mixture & Alligation
- Number System
- Partnership
- Percentage
- Problems on Ages
- Problems on Trains
- Profit/Loss & Discount
- Ratio & Proportion
- Simple & Compound Interest
- Simplification & Approximation
- Surds & Indices
- Time & Work / Pipes & Cisterns
- Trigonometry